Question

three times the smallest of three consecutive odd numbers decreased by 7 equal to twice the largest one .find the number​

Answer 1

Let the three consecutive odd numbers be x + 1, x + 3, x + 5

Three times the smallest number decreased by 7 = 3(x + 1) - 7 = 3x + 3 - 7 = 3x - 4

Twice the largest one = 2(x + 5) = 2x + 10

According to the question :

3x - 4 = 2x + 10

3x - 2x = 10 + 4

x = 14

Numbers : x + 1 = 14 + 1 = 15

x + 3 = 14 + 3 = 17

x + 5 = 14 + 5 = 19

Verification :

3(15) - 7 = 2(19)

45 - 7 = 38

38 = 38

LHS = RHS

So, my answer is correct.

Three consecutive odd numbers are 15, 17 and 19.