Question

Three times the sum of the digits of a 2-digit number is equal to the number itself. Find
the number.
HINT :- 3(a + b) = 10a+b
​

Answer 1

Answer:

3 (a+b)=10a+b

3a+3b=10a+b

7a-2b=0

7a=2b

a=2/7b here..... a and b is a digits so..value of b is only 7 is possible

so.. value of a is 2

so ..... no...is 27

I

hope it helps you

please mark as brainlest

Answer 2

Answer:

Let the number be:- ab

AB= 10a+b

Sum of digits= a+b

Three times the sum= 3(a+b)

3(a+b)= 10a+b

3a+3b= 10a+b

-b+3b= 10a-3a

2b= 7a

2/7b= a

So, the number is 27.

VERIFY:

3(a+b)= 10a+b

3(2+7)= 10×2+7

3×9= 20+7

27=27

LHS= RHS

Hence, verified

Hope it helps.

Please mark my answer as BRAINLIEST.