Question

Three tools are taken out of a tool box having ten different machine tools. If three out of 10 tools in the tool box are defective, what is the probability of taking out exactly two defective tools?​

Answer 1

Answer:

This is a very basic question of Probability. Consider two events,

A= No of ways of Selecting 2 tools from the three defective ones and 1 from the 7 non-defective ones

B= No of ways of Selecting 3 tools from the total 10 tools.

So A= (32).(71),          B=(103)

Hence the probability will be= AB=3×7120=740

Step-by-step explanation: