Question

Three trucks with wheels of circumference 50 cm ,60cm and 75 cm respectively start moving simultaneously to delivers the goods .What least distance should they cover so that each wheel makes complete number of revolution's​

Answer 1

Step-by-step explanation:

HERE WE FIND L. C. M. FOR SOLUTION OF THIS PROBLEM ,

50=2

$50 = 2 \times 5 \times 5$

$60 = 2 \times 2 \times 3 \times 5$

$75 = 3 \times 5 \times 5$

Finding LCM

$lcm = 2 \times 5 \times 5 \times 2 \times 3$

$lcm = 300$

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Answer 2

Answer:

Simple do l.c.m. of 50,60,75,100.

5 |50,60,75,100

3 |10,12,15,20

2 |10,4,5,20

2 |5,2,5,10

5 |5,1,5,5

|1,1,1,1. so least common multiple of these 4 numbers =5×3×2×2×5=300 . so distance travelled =2π(300)=600π=1884cm approximately .

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