Question

Three types of coffee beans, A, B and C, are blended in the ratio 3:5:7 to make a bag of coffee powder.
0 Given that the bag contains 45 kg of coffee powder, find the mass of each type of coffee beans in the
mixture.
A costs $7 per kg, B costs $10 per kg and C costs $13 per kg, find the cost per kg of the mixture.​

Answer 1

Let the beans be as follows 3x,5x,7x

ATQ 3x+5x+7x=45

15x=45

x=3

So weight of A=3*3=9 kg

Weight off B=5*3=15

Weight of C=7*3=21

Cost of A=7*9=63

Cost of B=15*10=150

Cost of C=21*13=273

Total =486/45=10.8

Answer 2

Answer:

(a)45 (b)12

Step-by-step explanation:

(a)

some toys= x, books=36,Total=36+x

x=5/9*(36+x)

9x=180+5x /9

9x-5x=180

4x=180

x=45 toys.

(b) books:toys=12:11

toys given away=y ,Total of books and toys=36+45-y

total ratio=23

36=12/23*(36+45-y)

36*23=12(81-y)

828=972-12y

12y=972-828

12y=144

y=12,

12 toys were given away.