Question

Three types of tea a ,b and c cost rs.95/kg,100/kg and 70/kg respectively. How many kgs of each should be blended to produce 100 kg of mixture worth rs.90/kg,given that the quantities of band c are equal

Answer 1

Answer:

50 kg of a, 25 kg of b and 25 kg of c

Step-by-step explanation:

Define x:

Let the quantity of b be x

The quantity of c = x

The quantity of a = 100 - x - x = 100 - 2x

Find the price for 100 kg:

1 kg = Rs 90

100 kg = 90 x 100 = Rs 9000

Solve x:

The total cost is Rs 9000

95(100 - 2x) + 100x + 70x = 9000

9500 - 190x + 100x + 70x = 9000

20x = 500

x = 25 kg

Find the quantity of each type:

b = x = 25 kg

c = x  = 25 kg

a = 100 - x = 100 - 2(25) = 50 kg

Answer: 50 kg of a, 25 kg of b and 25 kg of c

Answer 2

Answer:

50,25,25

Step-by-step explanation:

let qty of b and c are x

then qty of a is 100 - 2x

cost of each,

a -> 95(100-2x)

b -> 100x

c -> 70*x = 70x

and total cost of the mixture is 90*100

therefore

95(100 -2x) + 100x + 70x = 90*100

=> 9500 - 190x + 170X = 9000

=> 9500 - 9000 = 20x

=> x = 500/20

=> x = 25

therefore qty of B and C is 25 kg each

and qty of A is 50 kg (100 - 25 -25)