three unbaised coins are tossed simultaneously. find probability of getting at most two heads.
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Answer:
7/8 is the probability
Step-by-step explanation:
sample space=2^3=8
{HHH,HHT,HTH,THH,THT,TTH,HTT,TTT}
atleast two heads
={HHH,HHT,HTH,THH}
atmost two heads
={HHT,HTH,THH,THT,TTH,HTT,TTT}
probability of Atleast two heads
=4/8=1/2
probability of atmost two heads
=7/8
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