Question

three unbaised coins are tossed simultaneously. find probability of getting at most two heads.​

Answer 1

Answer:

7/8 is the probability

Step-by-step explanation:

sample space=2^3=8

{HHH,HHT,HTH,THH,THT,TTH,HTT,TTT}

atleast two heads

={HHH,HHT,HTH,THH}

atmost two heads

={HHT,HTH,THH,THT,TTH,HTT,TTT}

probability of Atleast two heads

=4/8=1/2

probability of atmost two heads

=7/8