Question

three unbaised coins are tossed together.find the probability of getting at least two heads​

Answer 1

Step-by-step explanation:

SS =

HHH

TTT

HTH

HHT

THT

TTH

HTT

THH

Favorable outcomes= HHH. HTH. HHT. THH

P = 4/8

= 1/2

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Answer 2

Answer:

Total probabilities (T) - 8

(TTT) (TTH) (THH) (HHH) (HTT) (HHT) (HTH) (THT)

P of at least 2 heads (P) - 4

(THH) (HHH) (HHT) (HTH)

Probability of an event = P/T

                                        = 4/8

                                        = 1/2 -OR- 50%

Hope this helped!