Question

Three unbaised coins are tossed together find the probability of getting exatly 2 heads and at least two heads

Answer 1

Step-by-step explanation:

Three unbiased coins are tossed so the sample space is

S  = { HHH , HHT , HTH , THH , HTT,  THT,  TTH , TTT }

n (S) = 8

Let   A  be an event to get exactly two heads

Therefore A = { HHT , HTH , THH ,}

n (A) = 3

Therefore P (A) = n (A) / n (S)

                          = 3/8

Let  B  be an event to get at least two heads

Therefore B = { HHH , HHT , HTH ,THH }

n (B) = 4

P (B) = n (B) / n (S)

       = 4/8

       = 1/2

Probability of event A is 3/8 and probability of event B is 1/2.

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Answer 2

Answer:

answer= a(3), b(4)