Question

three unbaised coins are tosses. whats the probability of getting at most one head​

Answer 1

Total no of probabilities=8

for 1 heads probability is =4

So we can include HHH, because it contains 0 heads.

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}  

Let E = event of getting at most one heads.

Then E = {THH, HTH, HHT,HHH}.  

P(E)=  n(S)

n(E)   =  4/8=1/2  

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