three unbiased coined are tossed . what is the probability of getting at most two heads ???
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Answer:
THE ANSWER IS 1/2
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Total outcomes = 8
(H,H,H) (H,H,T) (H,T,H) (H,T,T) (T,H,H) (T,H,T) (T,T,H) (T,T,T)
Possible outcomes for getting at least 2 heads are
(H,H,H), (H,H,T), (H,T,H), (T,H,H) = 4
Required probability is 4 / 8 = 1 / 2
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