Question

Three unbiased coins are tossed once. Find the probability of getting
at least 2 tails.​

Answer 1

Answer:

3/6 =1/2 the probability of getting

at least 2 tails.

Answer 2

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We know that ,

Probability of occurrence of an event

$= \frac{total \: number \: of \: desired \: outcomes \: }{total \: number \: of \: outcomes}$

Let T be tail and H be heads.

Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH.

Desired outcomes are at least two tails. So, the desired outputs are

TTH, THT, HTT, TTT

Total no.of outcomes are 8 and desired outcomes are 4.

Therefore, the probability of getting at least 2 tails= 4/8

=1/2

Conclusion:

Probability of getting at least two tails is

1/2.

Hope it helps you...

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