Question

Three unbiased coins are tossed once. Find the probability of getting atmost 2 tails or atleast 2 heads​

Answer 1

Answer:

1) 7 / 8

2) 1 / 2

Step-by-step explanation:

Heya friend,

Here we go :

Sample space when three unbiased coins are tossed once :

{HHH , HHT , HTH , THH , TTT , TTH , THT , HTT}

So,

Total outcomes = 8

Now, let's see both the parts :-

1) Probability of getting at most 2 tails

Here, the favorable cases would be the outcomes with 2 tails, 1 tail or no tail

Favorable case(s) = { HHH , HHT , HTH , THH , TTH , THT , HTT }

Probability = $\frac{7}{8}$

2) Probability of getting at least 2 heads

Here, the favorable cases would be the outcomes with 2 heads or 3 heads.

Favourable case(s) = {HHT, HTH , HHT , THH }

Probability = $\frac{4}{8}$

Probability= $\frac{1}{2}$

Thanks !

#BAL #answerwithquality

Answer 2

Answer:7/8

Step-by-step explanation:Atmost 2 tails means there should be 2 tails and not more than that at least two heads means there should be not less than 2 heads