Math, asked by bhabanid880, 3 months ago

Three unbiased coins are tossed simultaneously. What is the probability of getting atmost 2 heads?

Answers

Answered by khushi908494

For fairly tossed fair coins the number of possible outcomes = 2^3 =8.

They are: TTT, HTT, THT, TTH, HHT, HTH, THH, HHH.

(i) Getting 3H…..1 way. Probability = 1/8.

(ii) Getting 2H….3 ways. Probability = 3/8.

(iii) Getting 1H….3 ways. Probability = 3/8.

Getting____0H…..1 way. Probability = 1/8.

(iv) Getting at least 1H probability = probability of either 1H, 2H or 3H = (1/8)+(3/8)+(3/8) = 7/8.

(v) Getting at least 2H probability = probability of either 2H or 3H = (3/8)+(1/8) = 1/2.

(vi) Getting at most 2H probability = probability of either 0H, 1H or 2H = (1/8)+(3/8)+(3/8) = 7/8.

Answered by usernametaken8

Total number of outcomes are 8(2×2×2)

Number of unfavorable outcomes(i.e. Three consecutive heads in all three coins)=1

Therefore, (8-1)/8=7/8

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