Question

three unbiased coins are tossed together . find the probability of getting all heads (2) exactly 2 heads (3) at least 2 head (4) at most two balls

Answer 1

P(E) = No. of favourable outcomes/ Total No. of favourable outcomes.

Possible Outcomes :-

• HHH
• HHT
• HTH
• TTT
• TTH
• THT
• TTH
• HTT
• THH

P ( Getting all head ) = 1/8

P(Exactly two head ) = 3/ 8

P( At least two head ) = 4/8 = 1/2

Answer 2

Answer:

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