Three unbiased coins are tossed together. Find the probability of getting (i) at least two heads,
(ii) almost two heads , (iii) no tail, (iv) exactly one head.
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Answered by
3
Answer:
When 3 unbiased coins are tossed, the sample space is {HHH, HTH, HHT, THH, THT, TTH, HTT, TTT] = 8
WHICH GIVES US
Event of getting two heads = {HTH, HHT, THH} = 3
P(Two Heads) = 3/8
NOW CHECKING FOR TWO HEADS
Event of getting At least two heads (two or more than 2 heads) = {HHH, HTH, HHT, THH} = 4
P(At least Two Heads) = 4/8 = 1/2
Event of getting No heads = {TTT} = 1
P(No Heads) = 1/8
Step-by-step explanation:
Answered by
0
Answer:
1-2/3
2-2/3
3-0
4-1/3
please mark me as the brainleast
Step-by-step explanation:
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