three unbiased coins are tossed what is the probability of getting at least two heads
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Three events=head & tail, tail & head, head & head
P(A) =given/total
=3/3=1
P(A) =given/total
=3/3=1
gsehrawat:
this is wrong
how
because the total outcomes must be 9
or 6
okk
can you tell favourable outcomes
no sorry i don't know
ok
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