Three urns are given each containing red and white chips as given below Urn I: 6 red 4 white ;Urn II: 3 red 5 white;Urn III: 4 red 6 white An urn is chosen at random and a chip is drawn from the urn.(i) Find the probability that it is white.(ii) If the chip is white find the probability that it is from urn III
Answers
Step-by-step explanation:
I assume you mean that a randomly-selected ball is transferred? in that case we have a 4/9 chance of transferring a white ball (and a 5/9 chance of transferring a black ball of course).
If we transferred a white ball, there would then be 6 white and 4 black balls in the second container, meaning that if you selected a ball at random, there would be a 60% chance of selecting white.
On the other hand, if you transferred a black ball, there would be 5 white and 5 black balls in the second container, meaning that if you selected a ball at random, there would be a 50% chance of selecting white.
So the odds should be 4/9*6/10 + 5/9*5/10 = 54.4%
Answer:
Step-by-step explanation:
If we transferred a white ball, there would then be 6 white and 4 black balls in the second container, meaning that if you selected a ball at random, there would be a 60% chance of selecting white.
On the other hand, if you transferred a black ball, there would be 5 white and 5 black balls in the second container, meaning that if you selected a ball at random, there would be a 50% chance of selecting white.
hope it helps..