Three vertices of a parallelogram ABCD are A(–2, –2), B(2, 1), and C(0, 7). What are the coordinates of the vertex D in this parallelogram?
(–4, 4)
(4, 10)
(0, –8)
None of the above
Answers
Answered by
1
none of above in my opinion
Answered by
2
let coordinate of D be (x,y)
length of AB =CD
√(1+2)^2 +(2+2)^2 = √(y-7)^2 + (x-0)^2
9+16 = x^2 + y^2 +49 -14y
by solving this eq you get the answer
length of AB =CD
√(1+2)^2 +(2+2)^2 = √(y-7)^2 + (x-0)^2
9+16 = x^2 + y^2 +49 -14y
by solving this eq you get the answer
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