three vertices of a parallelogram ABCD are A(3,-1,2), B(1,2,-4), C(-1,1,2). Find the fourth vertex
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GIVEN POINTS ARE
A ( 3 , -1 ,2 ) = ( x1 , y1, z1 )
B ( 1, 2 , -4 ) = ( x2, y2 , z2 )
C ( -1 , 1 , 2 ) = ( x3 , y3 , z3 )
Let the fourth vertex be D = ( x4 , y4, z4 )
MISSING VERTEX FORMULA
D = ( x1 + x3 - x2 , y1 + y3 - y2 , z1 +z3 - z2 )
D = ( 3 -1 -1 , -1+1-2 , 2+2+4 )
D = ( 1 , -2 , 8 )
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