Three vertices of a parallelogram are (1,0) 2 0 5 1
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1
Answer:
this you solve by _/x1(y3-y2)x2(y2-y1)x3(y2-y1)
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0
Answer:
The point is D(4,1)
Step-by-step explanation:
I am guessing you want us to find fourth vertex.
Const. - Join the diagonals of the parallelogram.
We know that the diagonals of a parallelogram bisect each other.
Assume the centere point as O(a,b) and fourth vertex as (x,y)
On line segment AOC,
O((1+5)/2, (0+1)/2) = O(3, 1/2) -----[1]
On line segment BOD
O((2+x)/2, (0+y)/2) ------[2]
From [1] & [2]
2+x = 6 ⇒ x = 4, 1/2 = y/2 ⇒ y = 1
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