Math, asked by Jaisinghal6221, 10 months ago

Three vertices of a parallelogram are (1,0) 2 0 5 1

Answers

Answered by artisingh971456
1

Answer:

this you solve by _/x1(y3-y2)x2(y2-y1)x3(y2-y1)

Answered by achubadyal4
0

Answer:

The point is D(4,1)

Step-by-step explanation:

I am guessing you want us to find fourth vertex.

Const. - Join the diagonals of the parallelogram.

We know that the diagonals of a parallelogram bisect each other.

Assume the centere point as O(a,b) and fourth vertex as (x,y)

On line segment AOC,

O((1+5)/2, (0+1)/2) = O(3, 1/2)    -----[1]

On line segment  BOD

O((2+x)/2, (0+y)/2)                    ------[2]

From [1] & [2]

2+x = 6 ⇒ x = 4,   1/2 = y/2 ⇒ y = 1

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