three vertices of a parallelogram are A(-2, 3), B(6,7) and C(8, 3). Find the fourth vertex D
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Hi,
Here is your answer,
Let us consider fourth vertex as D (a,b)
Midpoint of AC = Mid point of BD
{(-2+8)/2,(3+3)/2} →{(6 +a)/2 , (7+b)/2}
Mid point formula→ {( x₁+x₂)/2 ,(y₁ +y₂)/2}
{6/2 , 6/2} → {(6 +a}/2 , (7+b)/2}
6/2 → (6 +a) / 2 , 6/2 → (7+b) /2
6 → 6 +a , 6 → 7 + b
6 -6→ a , 6 -7 → b
a →0 , b → -1
∴ The 4th vertex is {0,-1}
Here is your answer,
Let us consider fourth vertex as D (a,b)
Midpoint of AC = Mid point of BD
{(-2+8)/2,(3+3)/2} →{(6 +a)/2 , (7+b)/2}
Mid point formula→ {( x₁+x₂)/2 ,(y₁ +y₂)/2}
{6/2 , 6/2} → {(6 +a}/2 , (7+b)/2}
6/2 → (6 +a) / 2 , 6/2 → (7+b) /2
6 → 6 +a , 6 → 7 + b
6 -6→ a , 6 -7 → b
a →0 , b → -1
∴ The 4th vertex is {0,-1}
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