Three vertices of a parallelogram taken in order are (0, 3), (0, 0) and (5, 0), then fourth vertex is
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Let A(-1, 0), B(3, 1), C(2, 2) and D(x, y) be the vertices of a parallelogram ABCD taken in order. Since, the diagonals of a parallelogram bisect each other.
∴ Coordinates of the mid-point of AC=Coordinates of the mid-point of BD
⇒(
2
−1+2
,
2
0+2
)=(
2
3+x
,
2
1+y
)
⇒(
2
1
,1)=(
2
3+x
,
2
y+1
)
⇒
2
3+x
=
2
1
and
2
y+1
=1
⇒x=−2andy=1
Hence, the fourth vertex of the parallelogram is (-2, 1)
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