three vertices of a parallelogram taken in order are (1,1), (4,4) and (4,8). find the fourth vertex and the area of the parallelogram.
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In parallelogram diagonals bisect each other
Hence, mid point of AC=mid point of BC
Area of parallelogram =base ×height
Base =(4-1)=3 units
Height =(8-4)=4 units
Area 12 sq units
Hence, mid point of AC=mid point of BC
Area of parallelogram =base ×height
Base =(4-1)=3 units
Height =(8-4)=4 units
Area 12 sq units
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