Question

Three vertices of a rectangle are A (-2,0) , B (3,0) and C (3, - 3). find fourth vertex and find intersection point of their diagonal.

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Answer 1

Step-by-step explanation:

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Answer 2

Given three vertices of a rectangle are A(2,−1),B(2,7)andC(4,7).

These points are marked on the graph shown below.

Join the points to form rectangle ABCD.

Also join the diagonals AC and BD

The coordinates of fourth vertex D is (4,−1)

(ii) The midpoint of CD is (4,3).

By using distance formula

AB=

(x

2

−x

!

)

2

+(y

2

−y!)

2

=

(2−2)

2

+(7−(−1))

2

=

8

2

=8

BC=

(4−2)

2

+(7−7)

2

=

2

2

=2

Area of rectangle=AB×BC

=8×2

=16sq.units

solution