Question

Three vessels contain 1 by 5 litres,3 by 10 litres and 3 by 8 litres of milk these vessels are
emptied into an empty can. How much milk is there in the can?​

Answer 1

$Solution :$

••• Step - 1 •••

• Capacity of 1st vessel = 10 l

  Milk : Water = 2 : 1

  Ratio sum = 2 + 1 = 3

  Milk = (2/3) × 10 = (20/3) l

  Water = (1/3) × 10 = (10/3) l

• Capacity of 2nd vessel = 10 l

  Milk : Water = 3 : 1

  Ratio sum = 3 + 1 = 4

  Milk = (3/4) × 10 = (15/2) l

  Water = (1/4) × 10 = (5/2) l

• Capacity of 3rd vessel = 10 l

  Milk : Water = 3 : 2

  Ration sum = 3 + 2 = 5

  Milk = (3/5) × 10 = 6 l

  Water = (2/5) × 10 = 4 l

••• Step - 2 •••

Now, three vessels are emptied into a single large vessel.

  Total capacity = (10 + 10 + 10) = 30 l

  Milk = (20/3) + (15/2) + 6 = (121/6) l

  Water = (10/3) + (5/2) + 4 = (59/6) l

Milk : Water = (121/6) : (59/6) = 121 : 59

Answer 2

Answer:

$\frac{1}{5} +\frac{3}{10}+\frac{3}{8} = full can$

lcm=40

$\frac{1}{5} =\frac{8}{40} \\\frac{3}{10} =\frac{12}{40} \\\frac{3}{8} =\frac{15}{40} \\so, \frac{8}{40}+ \frac{12}{40}+\frac{15}{40}\\=\frac{35}{40}$

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Step-by-step explanation: