Question

Three vessels whose capacities are in ratio of 3 : 2 : 1 are completely filled with milk mixed with water. The ratio of milk and water in the vessels are 5 : 2, 4 : 1 and 4 : 1 respectively. Taking 1/3 of the first, 1/2 of second and 1/7 of third mixture, a new mixture kept in a new vessel is prepared. The percentage of water in the new mixture is

Answer 1

Answer:

Milk=76%

water=24%

Step-by-step explanation:

let capacity vessels is 3x,2x,x liter

Now taking vessels separately

====

Vessel I =

mixture taken out=3x*1/3= x liter

amt of milk= 5x/7,water=2x/7

=====================

Vessel II =

mixture taken out=2x*1/2= x liter

amt of milk= 4x/5,water=x/5

===============

Vessel III =

mixture taken out=x*1/7= x/7= 5x/35 liter

amt of milk= 4x/35,water=x/35

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Total milk=5x/7+4x/5+4x/35

1/35 *( 25x+28x+4x)= 57x/35

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total water= 2x/7 + x/5 +x/35

=1/35*(10x+7x+x)=18x/35

Total volume of mixture=x+x+x/7=2x+x/7=15x/7

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% Milk =100*57x/35 / 15x/7

=100*57x/35 * 7/15x=

=(100*57*7) / (35*15)

=39900/525

=76%

so water=100-76=24%

Answer 2

right answer is 24% for solution show this pic