Question

Three whole numbers have a total of 80.
The first number is a factor of 32.
The second number is 5 times the third number.
work out the three numbers.

Answer 1

Answer:

32 , 8 and 40.

Step-by-step explanation:

Since required numbers are Whole numbers, they can't be any decimal or negative number.

Let the third number be a and second number be 5a.

Since first number is a multiple of 32 it should be either 32 or 64 ( after 64 it will cross 80 and it will make the condition false ).

For 64 :

       ⇒ Sum of all numbers = 80

       ⇒ a + 5a + 64 = 80

       ⇒ 6a = 80 - 64

       ⇒ 6a = 16

       ⇒ a = 16 / 6

       ⇒ a = a decimal number.

a can't be a decimal number since it's a whole number as provided.

For 32 :

     ⇒ a + 5a + 32 = 80

     ⇒ 6a + 32 = 80

     ⇒ 6a = 80 - 32

     ⇒ 6a = 48

     ⇒ a = 48 / 6

     ⇒ a = 8

Therefore,

      third number is 8 and second number is 5( 8 ) ⇒ 40.

Hence numbers are 32 , 8 and 40.

Answer 2

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