three whose edges measure 3cm, 4cm, 5cm, respectively are melted to form a new cube find the surface area of the new cube formed
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VOLUME OF CUBE= a^3
S1=3 V=27
S2=4 V=64
S3=5 V=125
Sum of volumes of all 3 cubes= 3^3 + 4^4 + 5^5 = 27 + 64 +125 = 216
Volume of the new cube formed = 216
a = cube root of 216 =6
Surface area of the new cube formed = 6(a)^2
=6*6^2= 6*36= 216 sqcm.
S1=3 V=27
S2=4 V=64
S3=5 V=125
Sum of volumes of all 3 cubes= 3^3 + 4^4 + 5^5 = 27 + 64 +125 = 216
Volume of the new cube formed = 216
a = cube root of 216 =6
Surface area of the new cube formed = 6(a)^2
=6*6^2= 6*36= 216 sqcm.
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