Math, asked by ganesankumaresan33, 9 months ago

Three wires each of 30 ohm resistance, are arranged in parallel and connected to a battery
ef 10 lecianche cells, each having an EMF of 15 volts. The main current is
A) 0.1 amp
(B) 0.7 amp
(C) 0.375 amp
(D) 0.2 amp​

Answers

Answered by bhagyashreechowdhury
2

Given:

Three wires each of 30-ohm resistance

The wires are arranged in parallel and connected to a battery of 10 Leclanche cells

Emf of each Lechlanche cell = 15 volts

To find:

The main current

Solution:

Finding the total emf:

Let's assume that we have 10 Leclanche cells, each with an emf of 15 volts (say E₁ = 15 V, E₂ = 15 V ...... ), connected in a series combination having the same polarity.

Net Emf = E₁ + E₂ + ....... + E₁₀ = 15 + 15 + ..... (10 times) = 15 × 10 = 150 volts

Finding the equivalent resistance:

We have 3 wires each of 30 Ω (say R₁ = 30 Ω, R₂ = 30 Ω  & R₃ = 30 Ω) connected in parallel combination, therefore, net resistance in parallel combination is given by,

\frac{1}{R_e_q} = \frac{1}{R_1}  + \frac{1}{R_2}  + \frac{1}{R_3}

\implies \frac{1}{R_e_q} = \frac{1}{30}  + \frac{1}{30}  + \frac{1}{30}

\implies \frac{1}{R_e_q} = \frac{1+1+1}{30}

\implies \frac{1}{R_e_q} = \frac{3}{30}

\implies \frac{1}{R_e_q} = \frac{1}{10}

\implies \bold{R_e_q = 10\:ohms}

Now, Finding the main current through the circuit:

By using Ohm's Law, we have

\boxed{\boxed{\bold{I = \frac{V}{R} }}}

where

I = Current (in amperes)

V = Voltage (in volts)

R = Resistance (in ohms)

Here, we have

I = \frac{Net\:Emf }{Equivalent \:resistance} = \frac{Net \:Emf}{R_e_q}

\implies I = \frac{150}{10}

\implies \bold{I = 15\:A}

Thus, the main current through the given circuit is 15 A.

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Also View:

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a) the value of current through each resistor

b) the total current in the circuit

c) and the total effective resistance of the circuit

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four cells, each of EMF 2 volt and internal resistance 2 ohm are connected in parallel to form battery, the battery is connected to external resistance of 2.5 ohm and two resistance of 6 ohm and 3 ohm in parallel draw a circuit diagram and answer what is current in the main circuit? what is current in 6 ohm wire? what is drop in potential?

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Answered by ranjangyana161
0

Answer:

Step-by-step explanation:

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