three wires of 5 ohm , 10 ohm and 15 ohm are connected to a common point there other ends are free and give potential 8 volt , 6 volt 4 volt respectively . find the current flowing?
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Equivalent resistance equal to 5 + 10 + 15 Ohm= 30 ohm I=V/R I=30/30 I=1A Current through 10 ohm resistor will remain same that is equal to the total current in the circuit because the resistor is connected in series Now potential difference in the 10 ohm resistor V=IR V=1*10 V=10V
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