Question

three wires of length 48 m,80m,and96m are to be cut into equal pieces. find the greatest length of the pieces can be cut?

Answer 1

we have to find HCF
So factors of 48 = 1,2,3,4,6,8,12,16,24,48
factors of 80 = 1,2,4,5,8,10,16,20,40,80
factors of 96 = 1,2,3,4,6,8,12,16,24,32,48,96
CF = 1,2,4,8,16
HCF = 16
So it has to be cut in 16 m

Answer 2

Answer:

HCF of  48 m, 80 m and 96 m gives us the required length to be cut..

So factors of 48 = 1,2,3,4,6,8,12,16,24,48

factors of 80 = 1,2,4,5,8,10,16,20,40,80

factors of 96 = 1,2,3,4,6,8,12,16,24,32,48,96

CF = 1,2,4,8,16

HCF = 16  

So it has to be cut into 16 m