Question

Three workers can finish the job in days. How many workers joined to the initial three workers after days if the job was done days earlier?

Answer 1

Answer &

Explanation:

3 workers → 10days

after 2 days

3+x → d days

ATP,

x workers joined after 2 days and job was completed 2 days earlier. Therefore, total no. of working days d=6 days.

M1*D1=M2*D2

3*10=(3+x)*6

30=18+6x

12=6x

x=2

Hence, 2 workers joined after 2 days.