Question

Three years ago, a's age was thrice that of

b. two years hence a's age will be twice that of

b. what is the present age of a

Answer 1

hope this will help you

Answer 2

Answer:

6 years

Step-by-step explanation:

Let the present age of a be x

Let the present age of b be y

Three years ago a's age was x-3

Three years ago b's age was y-3

Since we are given that Three years ago, a's age was thrice that of  b.

⇒$x-3=3(y-3)$

⇒$x-3=3y-9$

⇒$x=3y-6$  --1

After two years a's age will be x+2

After two years b's age will be y+2

Since we are given that two years hence a's age will be twice that of  b.

⇒$x+2=2(y+2)$

⇒$x+2=2y+4$

⇒$x=2y-2$ --2

Equate 1 and 2

$2y-2=3y-6$

$y=4$

Substitute the value of y in 1 to get age of a

⇒$x=3(4)-6$

⇒$x=12-6$

⇒$x=6$

Hence the present age of a is 6 years