three years ago, a’s age was thrice that of b. two years hence a’s age will be twice that of b. what is the present age of a?
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Three years before b's age = x
Three years before a's age = 3x
present age of b = x + 3
present age of a = 3x + 3
After 2years age of b = x + 5
After 2years age of a = 3x +3+2 or 2(x+5)
3x + 5 = 2x + 10
x = 5
Present age of a = 3x +3 = 15 + 3 = 18years
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