Question

three years ago aman age was 11 times his son age . nine year hence the age of aman becomes 3 times his sin age that time the numeric value of the dum of squares of there preasent age

Answer 1

Answer:

Aman present age = 36 Yea

Son Present age = 6 year

Sum of square of their present age = 1332

Step-by-step explanation:

Let say Present age of Aman = A years

& present age of son = S Years

A -3 = 11 ( S -3)

=> A -3 = 11S - 33

=> A = 11S - 30

A + 9 = 3 (S + 9)

=> A + 9 = 3S + 27

=> A = 3S + 18

Equating both

11S - 30 = 3S + 18

=> 8S = 48

=> S = 6

A = 3*6 + 18

=> A = 36

Sum of square of their present age = 6² + 36² = 36 + 1296 = 1332

Answer 2

Answer:

1332

Step-by-step explanation:

Let the present age of man and his son be x and y respectively.

3 years ago

Age of man = x - 3

Age of son = y - 3

According to question, Man's age is 11 times that of his son

(x-3)=11 (y-3)      -------------------------------------------   equation (1)

9 years hence

Age of man = x + 9

Age of son = y + 9

According to question, Man's age is 3 times that of his son

(x+9) = 3(y+9) -------------------------------------------------- equation (2)

Solving both the equations:

x - 11 y = - 30

x - 3 y = 18

x = 36 y = 6

Thus,

Present age of man = 36 years

Present age of son = 6 years

Numeric value of sum of their present age = 36² + 6² = 1332