three years ago aman age was 11 times his son age . nine year hence the age of aman becomes 3 times his sin age that time the numeric value of the dum of squares of there preasent age
Answers
Answer:
Aman present age = 36 Yea
Son Present age = 6 year
Sum of square of their present age = 1332
Step-by-step explanation:
Let say Present age of Aman = A years
& present age of son = S Years
A -3 = 11 ( S -3)
=> A -3 = 11S - 33
=> A = 11S - 30
A + 9 = 3 (S + 9)
=> A + 9 = 3S + 27
=> A = 3S + 18
Equating both
11S - 30 = 3S + 18
=> 8S = 48
=> S = 6
A = 3*6 + 18
=> A = 36
Sum of square of their present age = 6² + 36² = 36 + 1296 = 1332
Answer:
1332
Step-by-step explanation:
Let the present age of man and his son be x and y respectively.
3 years ago
Age of man = x - 3
Age of son = y - 3
According to question, Man's age is 11 times that of his son
(x-3)=11 (y-3) ------------------------------------------- equation (1)
9 years hence
Age of man = x + 9
Age of son = y + 9
According to question, Man's age is 3 times that of his son
(x+9) = 3(y+9) -------------------------------------------------- equation (2)
Solving both the equations:
x - 11 y = - 30
x - 3 y = 18
x = 36 y = 6
Thus,
Present age of man = 36 years
Present age of son = 6 years
Numeric value of sum of their present age = 36² + 6² = 1332