Question

Three years ago, average age of 'A', 'B' and 'C' is 27 years. Four years hence, ratio of A and C's age is 7
: 10. IfB is 6 years younger than C, then find present age of 'A'?​

Answer 1

Answer ⤵

Let the present age of A, B and C be x, y and z years.

$⟹ \frac{(x - 3) + (y - 3) + (z - 3)}{3} = 27 \\ ⟹x + y + z = 90$

Also,

$⟹ \frac{y - 5 + z - 5}{2} = 20 \\⟹ y + z = 50 \\ ⟹x = 90 - 50 = 40years$

Means present age of X = A = 40years

@geniusbrain1