Question

Three years ago, my age was 5 times the age
of my son then. Six years ago, my age was
twice the square of the age of my son then.
Find the present age of my son.​

Answer 1

Answer:

10years

Step-by-step explanation:

present age of the son =X years

your age =Y years

according to the problem

Y-3=5(X-3)

Y=5X-12 ......(1)and

Y-6=2(X-6)^2

Y=2X^2-24X+78

so,we have from (1)

2X^2-29X+90=0

X=10 years