Math, asked by ll2988531, 4 months ago

Three years ago, Rahul was three times as old as his son and three years hence, twice his
age will be equal to five times that of his son. Find their present ages.​

Answers

Answered by PrincessTeja
4

Let us consider

Let us considerSon’s age = X

Let us considerSon’s age = XTwo years ago son’s age = X – 2

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2Given:

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2Given:5 × (X + 2) = 2 × (3X – 2)

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2Given:5 × (X + 2) = 2 × (3X – 2)5X + 10 = 6X – 4

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2Given:5 × (X + 2) = 2 × (3X – 2)5X + 10 = 6X – 4X = 14

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2Given:5 × (X + 2) = 2 × (3X – 2)5X + 10 = 6X – 4X = 14Son’s present age X = 14 years.

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2Given:5 × (X + 2) = 2 × (3X – 2)5X + 10 = 6X – 4X = 14Son’s present age X = 14 years.Father’s present age = (3 × 14) – 4

Let us considerSon’s age = XTwo years ago son’s age = X – 2His Father’s age at that time = 3(X – 2)Present age of Father = 3X – 6 + 2The present age of Father = 3X – 4Two years hence father’s age = 3X – 4 + 2Two years hence father’s age = 3X – 2Two years hence son’s age = X + 2Given:5 × (X + 2) = 2 × (3X – 2)5X + 10 = 6X – 4X = 14Son’s present age X = 14 years.Father’s present age = (3 × 14) – 4Father’s present age = 38 years

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