Question

three years ago Sonu Son was 5 years older than Reena. if he is Now twice as old as she is find their present ages​

Answer 1

Explanation:

let sonu's son age be 2x

rennas age be x

(x-3)+5=(2x-3)

x-3+5=2x-3

x+2=2x-3

5=x

hence sonu's son age is 2x=10 years

and Reena's age is x=5 years

Answer 2

Answer :

Sonu is 10 years old and Reena is 5 years old.

Step-by-step explaination :

Given :

3 years ago = Sonu was 5 years older than Reena

Presently, he's twice old as Reena

To find :

Their present ages

Solution :

Let the present ages be -

• Reena as y
• Sonu as 2y

Ages 3 years ago -

• Reena = (y - 3)
• Sonu = (2y - 3)

⇒ (2y - 3) = (y - 3) + 5

⇒ (2y - 3) = y + 2

⇒ 2y - y = 2 + 3

⇒ y = 5

Reena = 5 years old

$\rule{300}{1.5}$

★ Sonu =

⇒ 2 × 5

⇒ 10

Sonu = 10 years old

$\therefore$ Sonu is 10 years old and Reena is 5 years old.