Question

Three years ago, the difference in the ages of two brothers was two years. The sum of their present ages will be double in 10 years. What is the present age of the elder brother ?

Answer 1

Answer:

let the age of elder brother be x

and the age of younger brother be y

case1:A.T.Q

x-y=2.......................(1)

case 2: A.T.Q

x+y=10.......................(2)

adding equation (1) and (2)

x-y+x+y=2+10

2x=12

x=12/2

x=6

putting value of x in equation (1)

x-y=2

6-y=2

6-2=y

y=4

elder brother age =6years

younger brother age =4years

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

Assumption

Age of elder brother be p

Age of younger brother be n

Situation :-

p - n = 2 ......(Equation 1)

${\boxed{\sf\:{Second\; Situation}}}$

p + n = 10 ......(Equation 2)

Add (1) and (2) we get :-

p - n + p + n = 2 + 10

2p = 12

$\tt{\rightarrow p=\dfrac{12}{2}}$

p = 6

${\boxed{\sf\:{Substitute\;the\;value\;in\;(1)}}}$

p - n = 2

6 - n = 2

6 - 2 = n

n = 4

${\boxed{\sf\:{Elder\;Brother\;age}}}$

= 6 years

${\boxed{\sf\:{Younger\;Brother\;age}}}$

= 4 years