Three years ago,the difference in the ages of two brothers was 2 years. The sum of their present ages will double in ten years. What is the present age of the elder brother?
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Answer:
present age of the brothers = 9 and 11 years
age of the elder brother = 11 years
Step-by-step explanation:
let present ages of the brothers = x and y
3 years ago their ages = x-3 and y-3
given, (x-3) - (y-3) = 2
=> x-3-y+3 = 2
=> x-y = 2
=> x = y+2 -----(1)
10 years later their ages = x+10 and y+10
it is also given, (x+10) + (y+10) = 2(x+y)
=> x+y+20 = 2x+2y
=> x+y = 20
=> y+2+y = 20 [putting value of x from (1)]
=> 2y = 20-2 = 18
=> y = 9
=> x = y+2 = 9+2 = 11
So, present age of the brothers = 9 and 11
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