Math, asked by sharmila82, 2 months ago

Three years ago the father was 7 times as old as his son .three years hence the father's age would be 4 times that of his son .find present age of the father.​

Answers

Answered by shrirampawar249
19

Answer:

let father's age be x and son age be y

x - 3 = 7(y - 3) \\ x -  3 = 7y - 21 \\ x + 18 = 7y \\ after \: 3 \: years \:  \\ x + 3 = 4(y + 3) \\ x + 3 = 4y + 12 \\ x = 4y + 9 \\ subtracting \: bot \: the \: equatons \:  \\ x + 18 - x = 7y - 4y - 9 \\ 18 = 3y - 9 \\ 27 = 3y \\ 9 = y \\ x + 18 = 7y \\ x + 18 = 7 \times 9 \\ x + 18 = 63 \\ x = 45

father age is 45years

and sons age is 9 years

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