Three years ago, the population of a town was 50.000. If the annual increase during three successive
years at the rate of 5%, 4% and 3% respectively. What is its present population?
Answers
Answered by
0
Answer:
I am not so sure it would be 3 lakha
Answered by
1
Answer:
56,238
Step-by-step explanation:
Three years ago = 50,000
From this population, every year increasing of 5%, 4%, 3%
Here, the percentage is increasing. So, 100+5 = 105%, 100+4 = 104%, 100+3 = 103%
= 50000 × (105/100) × (104/100) × (103/100)
= 56238 (present population)
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