Question

Three years ago, the population of a town was 50.000. If the annual increase during three successive
years at the rate of 5%, 4% and 3% respectively. What is its present population?
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Answer 1

Answer:

I am not so sure it would be 3 lakha

Answer 2

Answer:

56,238

Step-by-step explanation:

Three years ago = 50,000

From this population, every year increasing of 5%, 4%, 3%

Here, the percentage is increasing. So, 100+5 = 105%, 100+4 = 104%, 100+3 = 103%

= 50000 × (105/100) × (104/100) × (103/100)

= 56238 (present population)