Math, asked by supriyasingh34, 11 months ago

three years ago the population of a town was 50000 if the annual increase during the three successive years at the rate of 5% 4% and 3% respectively what is its present population​

Answers

Answered by TiyashaMaity123
12

Answer:

increase in 1st year

5 \div 100 \times 50000 = 2500

2nd year

4 \div 100 \times 50000 = 2000

3rd year

3 \div 100 \times 50000 = 1500

recent population

2500+2000+1500=6000

50000+6000=56000

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