Question

three years ago, the population of a town was 50000.If the annual increase during three consecutive years be at the rate of 5 percent 4 percent and 3 percent what is the present population?

Answer 1

Hope it helps you mate!!!

Answer 2

Answer:

56784

Step-by-step explanation:

Population three years ago = 50000

The annual increase during three consecutive years be at the rate of 5 percent 4 percent and 3 percent

Population after increase of 5% = $50000+\frac{5}{100}(50000)=52500$

Population after increase of 4% = $52500+\frac{4}{100}(52500)=54600$

Population after increase of 3% = $54600+\frac{4}{100}(54600)=56784$

Hence The present population is 56784