Three years ago, the population of town was 50000. If the annual increase during three successive years be at the rate of 5%,4% and 3% respectively, what is its present population?
Answers
Hey User !
=) population when increase 5 percent
population when increase 5 percent= 50000x5/100
population when increase 5 percent= 50000x5/100=2500
population when increase 5 percent= 50000x5/100=2500population when increase 4percent
population when increase 5 percent= 50000x5/100=2500population when increase 4percent50000x4/100
population when increase 5 percent= 50000x5/100=2500population when increase 4percent50000x4/100=2000
population when increase 5 percent= 50000x5/100=2500population when increase 4percent50000x4/100=2000population when increase 3percent
population when increase 5 percent= 50000x5/100=2500population when increase 4percent50000x4/100=2000population when increase 3percent=50000x3/100
population when increase 5 percent= 50000x5/100=2500population when increase 4percent50000x4/100=2000population when increase 3percent=50000x3/100=1500
population when increase 5 percent= 50000x5/100=2500population when increase 4percent50000x4/100=2000population when increase 3percent=50000x3/100=1500total population =50000+2500+2000+1500
population when increase 5 percent= 50000x5/100=2500population when increase 4percent50000x4/100=2000population when increase 3percent=50000x3/100=1500total population =50000+2500+2000+1500=56238
Hope , It Helps .