Math, asked by aman187892, 1 year ago

Three years ago, the ratio between P's age and Q's
age was 9 : 5. After 2 years, P's age will be 17
years more than that of the 5 times the age of Q.
What is Q's present age.

Answers

Answered by MavisRee
0

Answer:

Step-by-step explanation:

Given that three year's ago, ratio of age of P and Q was 9 : 5

Let age of P three years ago be 9x

Let age of Q three years ago be 5x

Thus, present age of P  = 9x + 3 years

present age of Q  = 5x + 3 years

Also, given that after 2 years, age of P will be 17 years more than 5 times of age of Q

Age of P after two years  = 9x + 3 + 2 = 9x + 5 years

Age of Q after two years  = 5x + 3 + 2 = 5x + 5 years

We have

(\,9x + 5)\, = 17 + 5 \times (\,5x + 5)\,\\\\ 9x + 5 = 17 + 25x + 25\\\\

Here x will come in negative

Question is incorrect

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