Question

Three years ago, the ratio of ages of A and B was 7:1. After three years from 110w, the ratio of their ages will
be 4:1. What is the difference between their ages (in years) after seven years from now?​

Answer 1

Answer:

36

Step-by-step explanation:

A-3÷B-3 = 7

A+3÷B+3 = 4

on solving

A-7B = -18

A-4B = 9

B = 9

A = 45 (These are present ages)

Seven years from now

A's age = 52

B's age = 16

difference is 36

Answer 2

Given :- Three years ago, the ratio of ages of A and B was 7:1. After three years from now, the ratio of their ages will

be 4:1. What is the difference between their ages (in years) after seven years from now ?

Solution :-

Let us assume that, Three years ago, the age of A was 7x years and age of B was x years.

Than,

→ Present age of A is = (7x + 3) years.

→ Present age of B is = (x + 3) years.

So,

→ Age of A, 3 years from now = (7x + 3) + 3 = (7x + 6) years.

→ Age of B , 3 years from now = (x + 3) + 3 = (x + 6) years.

given that, ratio will be 4 : 1.

A/q,

→ (7x + 6) / (x + 6) = 4/1

→ (7x + 6) = 4(x + 6)

→ 7x + 6 = 4x + 24

→ 7x - 4x = 24 - 6

→ 3x = 18

dividing both sides by 3,

→ x = 6 .

Therefore,

→ Present age of A is = (7x + 3) = (7*6 + 3) = 42 + 3 = 45 years.

→ Present age of B is = (x + 3) = (6 + 3) = 9 years.

Hence,

→ Age of A after 7 years from now = 45 + 7 = 52 years.

→ Age of B after 7 years will be = 9 + 7 = 16 years.

So,

→ Difference between their ages = 52 - 16 = 36 years. (Ans.)

∴ Difference between their ages (in years) after seven years from now is 36.

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