Three years ago, the ratio of ages of A and B was 7:1. After three years from noww, the ratio of their ages will be 7:5 What is the difference between their ages (in years) after seven years from now?.
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Answers
Answer:
A-3÷b-3= 7
A+3÷b+3= 4
A- 7b= -18
A-4b= 9
B=9
A=45
seven years from now
A's age = 52
B's= 16
different is 36 answer.
☞GIVEN :
Three years ago, the ratio of ages of A and B was 7:1. After three years from noww, the ratio of their ages will be 7:5.
☞TO FIND :
What is the difference between their ages (in years) after seven years from now?
☞SOLUTION:
Let us assume that ,three years ago ,The age of A was 7x years and B was 1x years.
Than,
Age of A is = (7x +3 ) years
Present age of B is = ( 1x + 3) years
So,
→ Age of A ,3 years from now = (7x + 3) + 3 years = ( 7x + 6) years
→ Age of B ,3 years from now = (1x + 3) + 3 = (1x + 6) years
Given that ratio will be 4 : 1.
Hence,
☞(7x + 6 ) / (1x + 6) = 4/1
☞( 7x + 6 ) = 4(1x + 6)
☞7x + 6 = 4x + 24
☞7x - 4x = 24 -6
☞3x = 18
☞x = 18 /3
☞x = 6
Therefore,
Present age of A is =( 7x + 3 )= (7*6 +3)
= 42 + 3 = 45 years.
present age of B is = (1x + 3) = (1*6 + 3)
=6 + 3 = 9 years.
Hence,
Age of A after 7 years from now = 45 + 7 = 52 years.
Age of B after 7 years from now = 9 + 7 = 16 years.
SO,
Difference between their ages = 52 - 16 = 36 years.
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